For the function #f(x) = 1+3x-x^2#, what is #f(a+h) - f(a)#?

1 Answer
Feb 24, 2017

#= 3 h - 2ah -h^2 or h(3-2a-h)#

Explanation:

#f(a +h) -f(a)= [1+3 (a + h)-(a+h)^2)] - [1+3 a-a^2]#

#=1+3 a +3 h-(a^2+2ah+h^2)-1-3 a +a^2#

#=cancel 1+cancel (3 a) +3 h - cancel (a^2) -2ah -h^2-cancel 1- cancel (3 a) + cancel (a^2)#

#= 3 h - 2ah -h^2 or h(3-2a-h)#