# For the function f(x) = x^2 - 2x + 1, how do you solve f(x) = 0?

Jun 30, 2016

$x = 1$

#### Explanation:

If $f \left(x\right) = {x}^{2} - 2 x + 1$
when $f \left(x\right) = 0$
then ${x}^{2} - 2 x + 1 = 0$
and, factoring the left side,:
${\left(x - 1\right)}^{2} = 0$
$\Rightarrow x - 1 = 0$
$\Rightarrow x = 1$