Question

For the function `f(x) = x^2 - 2x + 1`, how do you solve f(x) = 0?

Answer 1

`x=1`

Explanation:

If `f(x)=x^2-2x+1`
when `f(x)=0`
then `x^2-2x+1=0`
and, factoring the left side,:
`(x-1)^2=0`
`rArr x-1=0`
`rArr x=1`