For the function #g(x)=x^3+x^2-6x#, how do you find g(1), g(-1)?

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Answer 1 · 2017-06-14T14:29:06

See a solution process below:

To find #g(1)# substitute #color(red)(1)# for each occurrence of #color(red)(x)# in #g(x)#:

#g(color(red)(x)) = color(red)(x)^3 + color(red)(x)^2 - 6color(red)(x)# becomes:

#g(color(red)(1)) = color(red)(1)^3 + color(red)(1)^2 - (6 * color(red)(1))#

#g(color(red)(1)) = 1 + 1 - 6#

#g(color(red)(1)) = -4#

To find #g(-1)# substitute #color(red)(-1)# for each occurrence of #color(red)(x)# in #g(x)#:

#g(color(red)(x)) = color(red)(x)^3 + color(red)(x)^2 - 6color(red)(x)# becomes:

#g(color(red)(-1)) = color(red)(-1)^3 + color(red)(-1)^2 - (6 * color(red)(-1))#

#g(color(red)(1)) = -1 + 1 + 6#

#g(color(red)(1)) = 6#