Question

For the reaction NH3 + O2 --> NO + H2O how many grams of O2 are needed to completely react with 85.15 g of NH3 ?

Answer 1

Approx...`200*g` with respect to `O_2`....

Explanation:

Now first we need the stoichiometric equation....to inform our calculations....

`2NH_3(g) + 5/2O_2(g) rarr2NO(g) +3H_2O(l)`

So is this balanced with respect to mass and charge? It the answer is no, then we are doomed from the outset. You must write a stoichiometrically balanced equation to inform your reasoning and calculation...

And if we start with `85.15*g` mass of ammonia...we got....

`(85.15*g)/(17.03*g*mol^-1)=5*mol`...and we need `5/4` equiv of dioxygen gas...a mass of `5/4xx5*molxx32.00*g*mol^-1=?*g`