For what value of #x# is the slope of the tangent line to #y=x^5 -x^2 +sinx# undefined?

2 Answers
Aug 17, 2017

No real #x# (the slope of the tangent line is well defined for all finite values of #x#)

Explanation:

The slope of the tangent is given by

#dy/dx = 5x^4-2x+cos x#

As this is well defined for all finite values of #x# the tangent line is well defined everywhere!

Aug 17, 2017

None

Explanation:

The slope of the tangent line to the graph of #y = x^5-x^2+sinx# at any point #x# is given by

#y' = 5x^4-2x+cosx#

#y'# is defined for all #x#, so the slope of the tangent line is defined for all #x#