For what values of x, if any, does f(x) = 1/(x^2-2x+1)  have vertical asymptotes?

May 17, 2018

$x = 1$

Explanation:

At $x = 1$, ${x}^{2} - 2 x + 1 = 0$,

so, ${\lim}_{x \rightarrow 1} f \left(x\right) = \infty$ and the line $x = 1$ is a vertical asymptote.