# For what values of x, if any, does #f(x) = 1/(x^2-3x+4) # have vertical asymptotes?

##### 1 Answer

Dec 15, 2016

There are no vertical asymptotes/

#### Explanation:

We can complete the square of the denominator:

So the denominator has its smallest values of

graph{1/(x^2-3x+4) [-3.328, 3.602, -0.978, 2.486]}