# For what values of x, if any, does #f(x) = 1/((x^2-4)(x+1)(x-5)) # have vertical asymptotes?

##### 1 Answer

Jan 13, 2016

#### Answer:

Vertical Asymptotes are

graph{1/((x^2-4)(x+1)(x-5)) [-4.083, 5.917, -2.5, 2.5]}

#### Explanation:

The given function

Notice the denominator

will be zero when x=2, x=-2, x=-1, x=5 and the value of the function at these values is not defined. These are the asymptotes (the vertical lines).

So, to determine these vertical lines, we simply, equate each factor of the denominator to zero.

also

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