# For what values of x, if any, does #f(x) = 1/((x-2)(x+2)(e^x-3)) # have vertical asymptotes?

##### 1 Answer

Feb 7, 2016

#### Explanation:

To find the vertical asymptotes you simply have to set the denominator of the fraction to

Hence, we are presented with 3 possible values for

Hence we have the equations of our vertical asymptotes

graph{1/((x-2)(x+2)(e^x-3)) [-5, 5, -2.5, 2.5]}

As you can see by the graph the asymptotes at our worked out locations are very distinct.