For what values of x, if any, does f(x) = 1/((x-3)(x-8))  have vertical asymptotes?

Jan 29, 2017

The vertical asymptotes are $x = 3$ and $x = 8$

Explanation:

As you cannot divide by $0$, $x \ne 3$ and $x \ne 8$

The domain of $f \left(x\right)$ is ${D}_{f} \left(x\right) = \mathbb{R} - \left\{3 , 8\right\}$

The vertical asymptotes are $x = 3$ and $x = 8$

graph{(y-1/((x-3)(x-8)))(y-50x+150)(y-100x+800)=0 [-2.33, 15.46, -5.26, 3.63]}