# For what values of x, if any, does f(x) = 1/((x-4)(x+6))  have vertical asymptotes?

x = 4 and x = $-$6..
f becomes infinity when x $-$ 4 = 0 or x + 6 = 0.
The graph is symmetrical about x = $-$1.
f = 0, when x = $\pm$ infinity. f = 0 is also an asymptote to the curve.