Question

For what values of x, if any, does `f(x) = 1/((x-6)(x^2-9))` have vertical asymptotes?

Answer 1

`x=6, x=3, x=-3`

Explanation:

Vertical asymptotes occur when the denominator equals zero.

`(x-6)(x^2-9)=0`

`(x-6)(x-3)(x+3)=0`

`x=6, x=3, x=-3`