For what values of x, if any, does #f(x) = 1/((x+8)(x-7)) # have vertical asymptotes?

1 Answer
Jul 30, 2018

Answer:

#"vertical asymptotes at "x=-8" and "x=7#

Explanation:

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non-zero for these values then they are vertical asymptotes.

#"solve "(x+8)(x-7)=0#

#x=-8" and "x=7" are the asymptotes"#
graph{1/((x+8)(x-7) [-10, 10, -5, 5]}