For what values of x, if any, does #f(x) = 1/((x+8)(x-7)) # have vertical asymptotes?

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Answer 1 · 2016-01-09T10:40:44

Vertical asymptotes: #x=-8# and #x=7#

#f(x) = 1/((x+8)(x-7))#

The vertical asymptotes are found when the denominator of the function becomes zero.

To find the Vertical asymptote we equate the denominator to zero.

#(x+8)(x-7)=0#

Using zero product rule we get

#x+8 = 0# or #x-7=0#

#=>x=-8# or #x=7#

Vertical asymptotes: #x=-8# and #x=7#