For what values of x, if any, does #f(x) = secx # have a vertical asymptote?

1 Answer

Answer:

In radians, the value of #x=pi/2+-n*pi" "#for #n=0, 1, 2, 3,4.....#
or
In degrees, the value of #x=90^@+-n*180" "#for #n=0, 1, 2, 3,4.....#

Explanation:

To solve for these values, we only need to know where sec x is undefined. Those values are quadrantal angles #pi/2, (3pi)/2, (5pi)/2, (7pi)/2, etc#

The vertical asymptotes are

#x=pi/2#
#x=(3pi)/2#
#x=(5pi)/2#
#x=(7pi)/2#
etc

God bless....I hope the explanation is useful.