# For what values of x, if any, does #f(x) = x/(xe^x-3) # have vertical asymptotes?

##### 1 Answer

Jan 2, 2016

#### Answer:

#### Explanation:

A vertical asymptote in a rational function will occur when the denominator is equal to

#xe^x-3=0#

This *cannot* be solved analytically. I recommend graphing the function and tracing the zero.

graph{xe^x-3 [-10, 10, -5, 5]}

Since

graph{x/(xe^x-3) [-10, 10, -5, 5]}