# For which non-zero real values of #x# is #-x^(-6) = (-x)^(-6)# ?

##### 1 Answer

Feb 16, 2018

None

#### Explanation:

If

#-x^(-6) = -1/(x^2)^3 < 0#

#(-x)^(-6) = 1/((-x)^2)^3 = 1/(x^2)^3 > 0#

So they cannot be equal.