# For which non-zero real values of x is -x^(-6) = (-x)^(-6) ?

Feb 16, 2018

None

#### Explanation:

If $x \ne 0$ then ${x}^{2} > 0$ and we find:

$- {x}^{- 6} = - \frac{1}{{x}^{2}} ^ 3 < 0$

${\left(- x\right)}^{- 6} = \frac{1}{{\left(- x\right)}^{2}} ^ 3 = \frac{1}{{x}^{2}} ^ 3 > 0$

So they cannot be equal.