Four cells each of internal resistance 1 ohm and e.m.f. 1.9v are connected to a external resistance of 18 ohm. find the terminal potential difference of this combination?

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Answer 1 · 2017-08-24T14:32:17

The potential difference is #=6.22V#

We apply the equation

#U=RI#

#E-U=rI#

#E=(R+r)I#

The emf is #E=4*1.9=7.6V#

The total resistance is

#r+R=4*1+18=22Omega#

The current is

#I=7.6/22=0.35A#

So, the potential difference is

#=U=18*0.35=6.22V#