#g(x)=(x-1)/(x+1), x=(z+1)/(1-z) #.Then#(dg)/dz=#?(Express it in z)
#g(x)=(x-1)/(x+1), x=(z+1)/(1-z) # .Then#(dg)/dz=# ?(Express it in z)
1 Answer
Jun 29, 2018
Explanation:
By quotient rule:
Therefore,
This can be simplified: