Gas A effuses 0.68 times as fast as Gas B. If the molar mass of Gas B is 17 g/mol, what is the molar mass of Gas A?
1 Answer
Jul 10, 2017
Answer:
Explanation:
We can use Graham's law of effusion to solve this:
where

#(r_A)/(r_B)# is a number representing the ratio of effusion rates of gas A to gas B, in this case#0.68:1 = 0.68# 
#M_A# and#M_2# are the molar masses of gases A and B, respectively.
We know the molar mass of gas B is
rounded to