# 25 liters of neon has a pressure of 125 kPa and a temperature of 37 degrees C. What will the volume be if the temperature increases to 45 degrees C and the pressure decreases to 100 kPa?

$\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$
And so ${V}_{2} = \frac{{P}_{1} {V}_{1}}{T} _ 1 \times {T}_{2} / {P}_{2}$
=(125*kPa*25*L)/(310*K)xx(318*K)/(100*kPa)=??*L