Give the standard equation of the circle given(3,5) with diameter 16?

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Answer 1 · 2018-06-20T01:57:11

#(x-3)^2+(y-5)^2=64#

#(x-h)^2+(y-k)^2=r^2#

Where #(h,k)# is the center of the circle and #r# is the radius.

We know #h=3# and #k=5#, and #r=8#, since the radius is half of the diameter.

Plugging these values in for our circle equation, we get

#(x-3)^2+(y-5)^2=8^2#

#bar( ul( | color(white)(2/2)(x-3)^2+(y-5)^2=64color(white)(2/2)|)#

Hope this helps!