Given: 1.65 L of water added to 112 grams of sodium acetate (#NaC_2H_3O_2#). What is the concentration of the solution?

1 Answer
Jul 6, 2016

Answer:

#"Concentration"# #=# #"Moles of solute"/"Volume of solution"#

Explanation:

#"Concentration"# #=# #(112*cancelg)/(82.03*cancelg*mol^-1)xx1/(1.65*L)# #=# #0.828*mol*L^-1" with respect to sodium acetate"#.

We have assumed (reasonably) that volume would remain constant after dissolution.

Would the #pH# of this solution be greater or less than #7#; why?