# Given: 1.65 L of water added to 112 grams of sodium acetate (NaC_2H_3O_2). What is the concentration of the solution?

Jul 6, 2016

$\text{Concentration}$ $=$ $\text{Moles of solute"/"Volume of solution}$
$\text{Concentration}$ $=$ $\frac{112 \cdot \cancel{g}}{82.03 \cdot \cancel{g} \cdot m o {l}^{-} 1} \times \frac{1}{1.65 \cdot L}$ $=$ $0.828 \cdot m o l \cdot {L}^{-} 1 \text{ with respect to sodium acetate}$.
Would the $p H$ of this solution be greater or less than $7$; why?