Given #2x+y = 6#, what is (2,) (0,) (1,) ?

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Answer 1 · 2018-07-09T21:54:10

The missing values are #2#, #6#, and #4#.

You are given an equation and the #x# values of #3# coordinates. To find the missing #y# values, plug in each #x# value into the equation:

First, let's find the #y# value when #x = 2#:
#2(2) + y = 6#

#4 + y = 6#

#y = 2#

Now find #y# when #x = 0#:
#2(0) + y = 6#

#y = 6#

Finally find #y# when #x = 1#:
#2(1) + y = 6#

#2 + y = 6#

#y = 4#

Therefore, the missing values are #2#, #6#, and #4# .

Hope this helps!

Given #2x+y = 6#, what is (2,____) (0,____) (1,____) ?