Question

Given 3-x where `x <= 2` and `x^2` where `x >2`, how do you find f(2)?

Answer 1

`f(2)=1.`

Explanation:

Given that `f(x)=3-x,`x`<=2`
`f(x)=x^2,`x>`2.`

To find `f(2)` we examine the definition of `f(x)` in such a way that in it where `x=2` is allowed,

It is easy to see that when `x=2, f(x)=3-x.`

`:. f(2)=3-2=1.`