# Given 3-x where x <= 2 and x^2 where x >2, how do you find f(2)?

Jun 12, 2016

$f \left(2\right) = 1.$

#### Explanation:

Given that $f \left(x\right) = 3 - x ,$x$\le 2$
$f \left(x\right) = {x}^{2} ,$x>$2.$

To find $f \left(2\right)$ we examine the definition of $f \left(x\right)$ in such a way that in it where $x = 2$ is allowed,

It is easy to see that when $x = 2 , f \left(x\right) = 3 - x .$

$\therefore f \left(2\right) = 3 - 2 = 1.$