Question

Given 3-x where `x <= 2` and `x^2` where `x >2`, how do you find f(6)?

Answer 1

The value is `f(6)=36`

Explanation:

The function is:

`f(x)={(3-x , x<=2),(x^2,x>2):}`

The first step of calculating the value of such piecewise function is to find in which interval is the argument located:

Since `6>2`, the argument belongs to the second interval, so you have to apply the formula `f(x)=x^2`.

`f(6)=6^2=36`