Given #5y+4=ay#, what is the value of #a# when #y=2#?

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Answer 1 · 2017-01-26T21:47:11

#a = 7#

To solve this we need to substitute #color(red)(2)# for every occurrence of #color(red)(y)# in the equation from the problem and solve for #a#:

#5color(red)(y) + 4 = acolor(red)(y)# becomes:

#(5 xx color(red)(2)) + 4 = acolor(red)(2)#

#10 + 4 = 2a#

#14 = 2a#

#14/color(red)(2) = (2a)/color(red)(2)#

#7 = (color(red)(cancel(color(black)(2)))a)/cancel(color(red)(2))#

#7 = a#

#a = 7#