Question

Given θ = 60∘, 0∘ < α < 360∘ and α ≠ θ, find α, such that:?

Answer 1

Sine: `a=120`
Cosine: `a=300`

Explanation:

Since `sin` is positive in quadrants I and II, we know that `a` must be in quadrant II, with a `60` reference triangle. Since reference triangles in quadrant II occur on the `-x-`axis, which is 180 degrees, we know `a=(180-60)=120`

Cosine is positive in quadrants I and IV. Using the same process as above we can deduce `a=(360-60)=300`