Question

Given `A=((-1, 2), (3, 4))` and `B=((-4, 3), (5, -2))`, how do you find 3A?

Answer 1

`3A=((-3,6),(9,12))`

Explanation:

If `k` is a constant and `M=((m_(11),...,m_(c1)),(...,...,...),(m_(r1),...,m_(rc)))` is a matrix

then
`color(white)("XXX")k*M=((k*m_(11),...,k*m_(c1)),(...,...,...),(k*m_(r1),...,k*m_(rc)))`