Given a+3/4b=2a+34b=2 and b+3/4a=6b+34a=6. How do you find b/aba?

1 Answer
Miguel F.
Dec 26, 2015

Just solving the system would make possible to calculate b/aba.

Explanation:

Let us solve the system by the row reduction method.

  1. Let us multiply both equations by 4, in order to quit every fraction:
    4a+3b=84a+3b=8
    3a+4b=243a+4b=24

  2. Now, let us multiply the first equation by 3 and the second one by 4, in order to get the same coefficient for aa:
    12 a + 9b = 2412a+9b=24
    12a+16b=9612a+16b=96

  3. Now, let us substract both equations:
    -7b=-72 rightarrow b = 72/7−7b=−72→b=727

  4. We get aa from the first equation:
    a = 2 - 3/4 b = 2 - 3/4 cdot 72/7 = -40/7a=2−34b=2−34⋅727=−407

This way, the division b/aba equals {72/7}/{-40/7} = -72/40 = -9/5727−407=−7240=−95

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