# Given a geometric sequence A1=6, r=-5, how do you find the 5th term?

Mar 7, 2016

3750

#### Explanation:

In the standard geometric sequence:

a , ar , $a {r}^{2} , a {r}^{3} , a {r}^{4} , \ldots \ldots \ldots \ldots \ldots \ldots . . , a {r}^{n - 1}$

the nth term $= a {r}^{n - 1}$

here $a = A 1 = 6 , r = - 5 \mathmr{and} n = 5$

$\Rightarrow {a}_{5} = 6 \times {\left(- 5\right)}^{4} = 6 \times 625 = 3750$