Question

Given a right triangle ABC with right angle at C, if a is 4 and c is 8, what is b?

Answer 1

`b=4 sqrt(3) approx 6.928`

Explanation:

Assuming that `a` is the side opposed to the vertex `A`, `b` is the side opposed to the vertex `B` and `c` is the side opposed to the vertex `C`, we have that the hypotenuse is `c=8` and `a=4` is one of the two legs.

Then you can use the Pythagorean Theorem as follows:
`b=sqrt(c^2-a^2)=sqrt(8^2-4^2)=sqrt(64-16)=sqrt(48)=sqrt(16 * 3)=4 sqrt(3) approx 6.928`