Given #f(x)=1/(x-4)#, what is #f(1/2)#?

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Answer 1 · 2016-11-17T10:27:54

#f(1/2) = -2/7#

To solve this substitute #1/2# in every place there is an #x# and solve:

#f(1/2) = 1/(1/2 - 4)#

#f(1/2) = 1/(1/2 - (4/1)(2/2))#

#f(1/2) = 1/(1/2 - 8/2)#

#f(1/2) = 1/(-7/2)#

#f(1/2) = (1/1)/(-7/2)#

#f(1/2) = (-2*1)/(1*7)#

#f(1/2) = -2/7#