In ΔABC, BC is extended to D, and BA is extended to E as shown in the figure. ∠ACD = 110° and ∠ABC = 45°. Find ∠BAC and ∠EAC respectively.

Option 4 : 65° and 115°

**Given:** ΔABC, ∠ACD = 110° and ∠ABC = 45°

**Concept: **

The exterior angle made by a side of a triangle is equal to the sum of opposite adjacent angles.

Linear pairs: When two lines intersect at the point the adjacent angles made by them sum up to 180° i.e. θ1 + θ2 = 180°. (θ, be any angle.)

**Angle sum property of a triangle:** The sum of all the three interior angles of the triangles will sum up to 180°.

**Calculation: **

We know, ∠ABC + ∠BAC = 110°

∠BAC = 65°

Now we know,

∠BAC + ∠EAC = 180° (Linear Pairs)

∠EAC = 115°