Given f(x)=4x-3, g(x)=1/x and h(x)= x^2-x, how do you find h(1/x)?
1 Answer
Sep 13, 2017
Explanation:
#"to evaluate "h(1/x)" substitute "x=1/x" in "h(x)#
#rArrh(1/x)=(1/x)^2-1/x#
#color(white)(rArrh(1/x))=1/x^2-1/x#
#"we can express this as a single fraction"#
#"multiplt the numerator/denominator of "1/x" by "x#
#rArr1/x^2-x/x^2#
#"denominators are common so subtract the numerators"#
#"leaving the denominator as it is."#
#rArrh(1/x)=1/x^2-x/x^2=(1-x)/x^2#
