# Given f(x)=root3(x-8) how do you find f(-208) and f(8)?

Dec 1, 2016

$f \left(- 208\right) = - 6$
$f \left(8\right) = 0$

#### Explanation:

To evaluate $f \left(x\right)$ just substitute $x$ in $f$ expression...

$f \left(x\right) = \sqrt[3]{x - 8} \Rightarrow f \left(- 208\right) = \sqrt[3]{- 208 - 8} = \sqrt[3]{- 216} = \sqrt[3]{{\left(- 6\right)}^{3}} = - 6$

$f \left(x\right) = \sqrt[3]{x - 8} \Rightarrow f \left(8\right) = \sqrt[3]{8 - 8} = \sqrt[3]{0} = 0$