Given #f(x)= x^2/(x+2)# how do you find #-f(x)#?

1 Answer
Mar 24, 2017

Negative function - invert the signs. Inverse function - interchange the #x# and #y# variables.

Explanation:

The original function, #f(x) = x^2/(x+2)#, when introduced a negative, simply results in inverting all the signs.

As a result, you get: #-f(x) = -(x^2)/(x+2)#.

Please don't get confused with the inverse notation: #f(x)^-1#. Completely different than the negative function.

Hope this helps :)