# Given f(x)=x+8, g(x)=x+8, how do you find the values of x for which f(x)/g(x)=32?

As written, $f \frac{x}{g} \left(x\right) = 1$ for all values of $x$ and there are no values where it will equal anything other than 1. I suspect that one of the functions was mistyped.
For $f \frac{x}{g} \left(x\right)$ where $f \left(x\right) = x + 8 , g \left(x\right) = x + 8$, we end up with:
$\frac{x + 8}{x + 8} = 1$ for all values of $x$. So there are no values of $x$ where $f \frac{x}{g} \left(x\right) = 32$.