Given #h(x)=(3x)/(2x-17)#, how do you find h(7)?

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Answer 1 · 2016-10-27T14:46:38

#- 7#

#h(7) = [3 * 7]/[2*7 - 17] = 21/[-3] = - 7#

Answer 2 · 2016-10-27T14:46:39

#h(7) = -7#

To find #h(7)# you need to substitute #7# into every place there is an #x# in the equation and solve or:

#h(7) = 3*7 / ((2*7) - 17)#

#h(7) = 21 / (14 - 17)#

#h(7) = 21 / -3#

#h(7) = -7#