Question

Given `h(x) = 5x^2 - 4x` how do you find h(-3)?

Answer 1

It is `h(-3)=57`

Explanation:

Hence `h(x)=5x^2-4x` then just replace `x` for `-3`

#h(-3)=5*(-3)^2-4*(-3)=>h(-3)=45+12=> h(-3)=57#