Given log2=.3010 and log3+.4771, how do you evaluate #log(3/2)#?
1 Answer
Explanation:
Let's review a few important properties of logarithms, easily derived from its definition:
(1)
because
(2)
because
(3)
because
(4)
because
You can get more details about logarithms at Unizor by following the menu options Algebra - Logarithmic Functions.
Using the property (3) above,