# Given Log3=0.4772, log7=0.8451, log5=0.6990, log2=0.3010, how do you evaluate Log(2/15)?

##### 1 Answer

Aug 10, 2016

#### Answer:

I found:

#### Explanation:

I used the properties of logs concerning the product and the difference of the argument of the log to change them in sums or differences of logs: