Question

Given: `p(x) = -5absx + abs(-x + 1`, `h(x) = -x^2 - 3x`, and `g(x) = 5 - sqrt(x+30)`, how do you find g(-34)?

Answer 1

Note that the formulas for `p(x)` and `h(x)` are extraneous.

Given `g(x) = 5-sqrt(x+30)`

Therefore
`g(color(red)(-34)) = 5 - sqrt(color(red)(-34) +30)`

`g(-34) = 5-2i`