# Given: p(x) = -5absx + abs(-x + 1, h(x) = -x^2 - 3x, and g(x) = 5 - sqrt(x+30), how do you find g(6)?

##### 1 Answer
May 27, 2015

The equations for $p \left(x\right)$ and $h \left(x\right)$ are extraneous to the question.

Given $g \textcolor{red}{\left(x\right)} = 5 - \sqrt{\textcolor{red}{x} + 30}$

$g \left(\textcolor{red}{6}\right) = 5 - \sqrt{\textcolor{red}{6} + 30}$

$= - 1$