# Given: p(x) = -5absx + abs(-x + 1, h(x) = -x^2 - 3x, and g(x) = 5 - sqrt(x+30), how do you find p(3)?

The functions $h \left(x\right)$ and $g \left(x\right)$ appear to be extraneous.
Given $p \left(x\right) = - 5 \left\mid x \right\mid + \left\mid - x + 1 \right\mid$
$p \left(3\right) = - 5 \left\mid 3 \right\mid + \left\mid - 3 + 1 \right\mid$
$= - 15 + 2$
$= - 13$