Question

Given `sin x/ x^2` how do you find the limit as x approaches 0?

Answer 1

You should use the fact that `lim sinx/x = 1` as `x` approaches 0

Explanation:

You can modify the expression as follows:

`sinx/x^2 = sinx/x * 1/x`, and then taking the limits:

`lim sinx/x = 1`, and

`lim 1/x =oo`, so the end result is:

`lim sinx/x^2 = lim sinx/x * lim 1/x = 1 * oo= oo`