Given that #a:b = 7:9# and #b/c = 6/13#, what is (a) #a:c#, (b) #a:b:c: # and (c) #(2a)/(5c)#?

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Answer 1 · 2016-12-14T16:44:08

(a) 42:117, (b) 42:54:117 & (c) 84:585

Here #a/b = 7/9#.......(i)

& #b/c = 6/13#.............(ii)

Now multiply (i) equation by 6/6 and equation (ii) by 9/9

we get #a/b = 42/54 and b/c = 54/117#.

So we can write a:b:c = 42:54:117.

now (a) a:c = 42:117,

(b) a:b:c = 42:54:117 and (c) #[2a]/[5c] = [2*42]/[5*117] = 84/585#