Given that #a_n = 3n - 5# , what are the 56th and 71st terms?

1 Answer
Jul 26, 2016

163 and 208

Explanation:

This is a great way to be given the general term of a progression!

#n# stands for the number of the term - in this case #n= 56 and n = 71#

TO find the value of the actual terms, substitute for #n#.

#a_56 = 3(56) -5 = 168-5 = 163#

#a_71 = 3(71)-5 = 213 -5 = 208#