# Given that #cos x =p# find an expression, in terms of #p#, for #tan^2 x#?

##### 2 Answers

Oct 12, 2015

#### Explanation:

If cos x =p,

tan x =

Oct 12, 2015

#### Explanation:

If

#cos^2 x = p^2# .

By Pythagoras,

#sin^2 x = 1 - cos^2 x = 1 - p^2#

Now

#tan^2 x = sin^2 x / cos^2 x = (1 - p^2)/p^2 = 1/p^2 - 1#