# Given that P-31 is the only natural isotope of phosphorus, what is the mass of one P atom and the mass of Avogadro's number of P atoms?

Oct 22, 2017

""^31P is certainly the most abundant phosphorus isotope....
And it is a fact that one mole of phosphorus atoms has a mass of $31.0 \cdot g$....
$\frac{31.00 \cdot g \cdot m o {l}^{-} 1}{6.022 \times {10}^{23} \cdot m o {l}^{-} 1} = 5.15 \times {10}^{-} 23 \cdot g$....